Associativity controls the order in which operators are evaluated in a chain of operators of the same precedence.

If operand evaluation order was tied to operator precedence and associativity, bar() would be evaluated before foo() in 

foo() + bar() * baz()

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(It's not.)

In reply to Re^2: Will "$_[0]=shift" always resolve shift first? by ikegami
in thread Will "$_[0]=shift" always resolve shift first? by kyle

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