Actually that doesn't seem to me to contradict anything I wrote! You show a code fragment that is completely consistent (in fact illustrates) my assertion that "part of the LHS calculation is performed before the RHS is fully evaluated".

Besides, the under the hood machinations are unimportant. The effect and important point to note is that where the language does not contract to perform operations in any particular order, it doesn't have to and the results may be surprising. One might expect that $array[++$x] = ++$x; would be equivalent to:

++$x; $array[$x + 1] = $x; ++$x;

but that is not how Perl does it (at least for version 5.8.7). What Perl appears to do is:

++$x; ++$x; $array[$x] = $x;

Perl reduces RSI - it saves typing

In reply to Re^6: Will "$_[0]=shift" always resolve shift first? by GrandFather
in thread Will "$_[0]=shift" always resolve shift first? by kyle

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