use List::Util 'shuffle';
my @numbers = (1..10);
my $r1 = pop(shuffle(@numbers));
my $r2 =  pop(shuffle(@numbers));

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I get a pretty vague error (Unknown error) from the above code, but its from the pop's. I suppose thats because shuffle is returning a list (and therefore cannot be pop'd?). Whats an elegant way to get 2 unique random numbers between 1 and x? It seems like it involves an ugly amount of code to do such a trival task :(

In reply to Generating 2 unique random integers (So I can't pop a list...) by uG

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