The comments from FunkyMonk and toolic bring up a (possible) subtle difference in the "pattern",that I have always puzzled about.

--FunkyMonk
1 hash access, + possibly 1 scalar assignment

if (my $ans = $hash{$input}) { print "$input => $ans\n";

--toolic
1 hash access + possibly 1 more hash access
is the 1st result 'cached' and the second access reuses the 1st result?

if (exists $hash{$input}) { print $hash{$input}, "\n";


In reply to Re: the if statement by Wiggins
in thread the if statement by kwn

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