One character strings in Perl are still strings; not numbers as in C. So, $buffer == hex ('0x00') would match if, and only if, $buffer == 0, hence, if $buffer contains the character "0". And, as pointed out, when you write it, you write 0x17, aka 23, as digits.

Furthermore, hex('0x00') is redundant. It's equal to 0x00. The same with hex('0x17') which is the same as 0x17.

The right solution has already been mentioned; no need to repeat it.

In reply to Re: Binary conditionals by JavaFan
in thread Binary conditionals by bunnym4n

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