Hello, I have a problem in passing a multidimensional array into a function. Below is a code representing the problem. The function "change" changes some values ($array[0][1]) in the input and returns the array, but the values in the original and even the backup array also changes (so I suppose it must be an issue with pointers). It doesn't happen when the array is singular (meaning replace $array[0][1] with $array[0]). All the values are changed to 5 but I want the original or at least backup not to change. Does it have to do with the fact that a multidimensional array is really an array of pointers? 
use strict "vars";

main();

sub main
{
my @array;                 #original array
$array[0][1]=1;            #set one of its values
my @array2=@array;         #create a backup array

my (@newarray) = change(@array);  #feed it to a function


print "new array value is".$newarray[0][1]."\n";  #print
print "original array value is".$array[0][1]."\n";
print "array2 value is".$array2[0][1]."\n";
}

sub change
{
my (@array)=@_;                 #take input
$array[0][1]=5;                 #change value
return (@array);                #return
}

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In reply to Problem in Passing A Multidimensional Array into a Function by Anonymous Monk

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