$ matches the point between \n and the character before it.

print "a\n\nc\n" =~ / a\n ^ $ c\n /mx ?1:0, "\n"; # 0 print "a\n\nc\n" =~ / a\n ^ $ \n c\n /mx ?1:0, "\n"; # 1

Since $ matches before the newline, it doesn't ever actually match the newline, and thus the newline is not getting substituted. What you want to do is remove newlines that start lines.

$_ = "abc\n" . "def\n" . "\n" . "jkl\n" . "\n" . "\n" . "stu\n"; s/^\n//mg; print;
abc def jkl stu

In reply to Re: Having Trouble Removing a Newline from a Multiline String by ikegami
in thread Having Trouble Removing a Newline from a Multiline String by Dru

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