I am using Perl and I have a string such as the $testString below. I take the string and remove the trailing/leading whitespace. Then, I remove the spaces between the words. My last goal is to do a bitwise & operator (mask) to determine if the 2nd bit is a 1.

What I want in this example is an end output of 0. I get 4294967295 with an error saying "Argument "00008008000000FF00800000" isn't numeric in bitwise and (&) at .... line 16. Do I have to typecast the array to be an int? I thought you didn't have to do that. Please advise. 

#!/usr/bin/perl -w
# File displayPipeTracer2.pl

$testString = "          00008008 000000FF 00800000";
print "Original: $testString\n";

$testString =~ s/^\s+//; #remove leading spaces
$testString =~ s/\s+$//; #remove trailing spaces

print "Removed L/T: $testString\n";

$testString =~ s/\s//g;

print "Removed ws: $testString\n";

$maskResult = $testString & 400000000000000000000000;

print "Mask Result: $maskResult\n";

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In reply to Bitwise Operator Error by ravishi

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