Hello Everyone, I have this code misbehaving in one of my scripts, I have a var containing the sequential number of the day for the year and I am suppose to get the regular date for that day and its weekday. If I set the day to 273 I get back 2008/09/31 which is not a proper date. can you help me understand why? .................

syy=2008
newstart=272
perl -e 'use Time::Local; $yr = $ARGV[0] - 1900; $yday = $ARGV[1]; $my
+time = timelocal(1,0,0,1,1,$yr); $mytime += ( 86400 * $yday ); ($sec,
+$min,$hour,$day,$mon,$yr,$wday,$yday,$whocares) = localtime($mytime);
$yr += 1900; printf("%d/%02d/%02d%s", $yr, $mon, $day, " " );use POSIX
+ qw(strftime);$fmt = "%A"; # %a = abbreviated weekday %u = weekday nu
+mber;
$weekday = strftime($fmt, 0, 0, 0, $day , $mon - 1, $yr - 1900, -1, -1
+, -1);printf("%s%s%s", "$weekday"," ",$ARG[2]);' $syy $newstart >> pp
+pp

newstart=273
perl -e 'use Time::Local; $yr = $ARGV[0] - 1900; $yday = $ARGV[1]; $my
+time = timelocal(1,0,0,1,1,$yr); $mytime += ( 86400 * $yday ); ($sec,
+$min,$hour,$day,$mon,$yr,$wday,$yday,$whocares) = localtime($mytime);
$yr += 1900; printf("%d/%02d/%02d%s", $yr, $mon, $day, " " );use POSIX
+ qw(strftime);$fmt = "%A"; # %a = abbreviated weekday %u = weekday nu
+mber;
$weekday = strftime($fmt, 0, 0, 0, $day , $mon - 1, $yr - 1900, -1, -1
+, -1);printf("%s%s%s", "$weekday"," ",$ARG[2]);' $syy $newstart >> pp
+pp

newstart=274
perl -e 'use Time::Local; $yr = $ARGV[0] - 1900; $yday = $ARGV[1]; $my
+time = timelocal(1,0,0,1,1,$yr); $mytime += ( 86400 * $yday ); ($sec,
+$min,$hour,$day,$mon,$yr,$wday,$yday,$whocares) = localtime($mytime);
$yr += 1900; printf("%d/%02d/%02d%s", $yr, $mon, $day, " " );use POSIX
+ qw(strftime);$fmt = "%A"; # %a = abbreviated weekday %u = weekday nu
+mber;
$weekday = strftime($fmt, 0, 0, 0, $day , $mon - 1, $yr - 1900, -1, -1
+, -1);printf("%s%s%s", "$weekday"," ",$ARG[2]);' $syy $newstart >> pp
+pp

the contents of pppp:
2008/09/30 Tuesday 2008/09/31 Wednesday 2008/10/01 Wednesday
[download]

Thanks for your help.

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