Here a way of doing it with pos: 
my $x = "<0>";
my $pos = 0;
for (qw {<1> <2> <3>}) {
    pos($x) = $pos;
    $x =~ s/\G(<\d+>)/$1$_/;
    $pos += length $1;
}
say $x;
__END__
<0><1><2><3>

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In reply to Re: How to start regexp from a X position by JavaFan
in thread How to start regexp from a X position by pkt

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