Thank you very much for the elaborate reply. As you noted in your reply, the subroutines do return a new, completely different array. In that case, you mentioned:
"the values have to be copied one way or another. I'd write it different though:
sub foo {
my $array = shift;
my $copy = [map {[@$_]} @$array];
... Changes in $copy won't affect $array ...
return $copy;
}
As i can see, now $copy is a reference that points to an array of (a new set of) references, each of which contain the same elements as the corresponding reference in @original_array. It could be written in this way though.
sub foo {
my $array = shift;
my @copy = map {[@$_]} @$array;
... Changes in @copy won't affect @array ...
return \@copy;
}
right?
And is the reason that you'd copy the elements this way is that it's faster?
Again, thanks a lot for your tips,
Hadi
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