No, you've made things worse. buf needs to always be u_char * or u_char * &. u_char & is completely different.

Try again and/or reread what I wrote. You want $buf to hold an opaque UV that gets converted to/from a u_char *. Some of your calls should pass a reference to this u_char * rather than passing the u_char * directly (that is what the "&" is for). Those routines are the ones that might change the pointer (by allocating or reallocating the memory) and are also the ones that need buf mentioned in the OUTPUT: section.

        - tye (but my friends call me "Tye")

In reply to (tye)Re5: XS question: typemap for a pointer to a pointer? by tye
in thread XS question: typemap for a pointer to a pointer? by Big Willy

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