dear monks, i want to list the directories after checking if its available or not. example, "/home/folders/" has directories namely 'case1','case2','case3','case4', so on..... under each case, there are many directories, but i want to check for the availabilities of only 3 directories namely "SORTED", "CLEANED" and "PROCEED". The way i want to print the results is: (assuming that the "no"s are the directories which are absent in few of the cases).... 
CASENAME    SORTED  CLEANED  PROCEED
case1        yes     no         no
case2        yes     yes         yes
case3        no        yes         yes
case4         no        no         no

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What i have done so far is: (but am not getting the desired results) 
#!/usr/bin/perl
open(FILE,'>out.txt') or die $!;
if($one eq "option1"){
opendir(DIR,"/home/folders/") or die "can not open directory";
foreach my $line (sort grep !/^\./, readdir DIR){
print FILE "$line|";
opendir(DIR1,"/home/folders/$line");
foreach my $line1 (sort grep !/^\./, readdir DIR1){
if($line1=~/sorted/ && $line1=~/^\w/){print FILE "Yes|";}
elsif($line1=~/cleaned/ && $line1=~/^\w/){print FILE "Yes|";}
elsif($line1=~/proceed/ && $line1=~/^\w/){print FILE "Yes|";}
}
print FILE "\n";
}
}
close (FILE);
open(FILE1,'out.txt') or die $!;
print "CASENAME  SORTED CLEANED  PROCEED";
while($ln=<FILE1>){
($directory,$subdir1,$subdir2,$subdir3)=split(/\|/,$ln);
print "\n$directory\t";
if($subdir1 ne "Yes"){print "No\t";}else{print "Yes\t";}
if($subdir2 ne "Yes"){print "No\t";}else{print "Yes\t";}
if($subdir3 ne "Yes"){print "No\t";}else{print "Yes\t";}
}
close(FILE1);
unlink("out.txt");

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Thank u :)

In reply to printing the directories... by sugar

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