The difference between 
$s1 = ($x, $y) = 0..11;

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and 
$s2 = ($x, $y)

[download]
is that $s1 gets assigned the result of the list assignment operator, and $s2 gets assigned the result of the scalar comma operator. In neither case there's a list assigned to any of the $s? variables; in both cases the result of operators are assigned.

But as long as you keep believing in the existence of lists in scalar context, you'll keep being confused.

In reply to Re^5: If you believe in Lists in Scalar Context, Clap your Hands by JavaFan
in thread If you believe in Lists in Scalar Context, Clap your Hands by gone2015

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