If you can't have a list in a scalar context, how can you have the assignment of a list in scalar context? You have even said in this thread that lists don't even exist.

The list assignment imposes a list context on its operands. So while the list assignment is in scalar context, the assignee and assigned lists aren't. 

   A     B      C     D        <-- labels
$x = ( $i, $j ) = ( $p, $q ); 
S  ?   L L L    S   L L L      <-- context
|  |   | | |    |   | |  \__ Propogated by right-most list op'tor (D).
|  |   | | |    |   |  \____ Imposed by the list assignment (C).
|  |   | | |    |    \______ Propogated by right-most list op'tor (D).
|  |   | | |     \__________ Imposed by the scalar assignment (A).
|  |   | |  \_______________ Propogated by left-most list op'tor (B).
|  |   | \__________________ Imposed by the list assignment (C).
|  |    \___________________ Propogated by left-most list op'tor (B).
|   \_______________________ Determined by outside code.
 \__________________________ Imposed by scalar assignment (A).

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In reply to Re^9: If you believe in Lists in Scalar Context, Clap your Hands by ikegami
in thread If you believe in Lists in Scalar Context, Clap your Hands by gone2015

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