The result of the whole expression is what I'd say is in scalar context, actually. Assess the context here: 
perl -e 'print scalar( ($x, $y ) = ( 42, 101, 202 ) ); print "\n$x\n$y
+\n";'

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The assignment operator itself happens to be both in scalar and in list context. It produces both a list for the list, and a scalar for the function scalar(). Which oddly leads to the possibility of saying the assignment operator in this: 
perl -E 'say scalar(() = ($a, $b, $c))'

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... is both in scalar and void contexts.

I'm not sure how this is any more clear than saying there are exceptions to a general rule about lists returning something of their own accord.

In reply to Re^12: If you believe in Lists in Scalar Context, Clap your Hands by mr_mischief
in thread If you believe in Lists in Scalar Context, Clap your Hands by gone2015

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