The assignment operator itself happens to be both in scalar and in list context. It produces both a list for the list, and a scalar for the function scalar().
No. The assignment operator does the assignment, but it doesn't produce a list. The assignment is the side-effect; the result is a scalar due to the scalar context. Similar to how the ++ in perl -we'print $i++' produces 0 while incrementing $x.
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In reply to Re^13: If you believe in Lists in Scalar Context, Clap your Hands by ysth
in thread If you believe in Lists in Scalar Context, Clap your Hands by gone2015

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