The post says:

And this needs to be very fast since in use it's going to have to handle sums of up to 10^6.

I don’t think your program can be used for this; it only works for small integers.

The so-called partition function p(n) represents the number of possible partitions of a natural number n (distinct and order independent). Unfortunately p(n) grows rapidly, see Partition. Try to run the program on n=1000.

In reply to Re^2: Decomposing sum to unique sets of summands by dHarry
in thread Decomposing sum to unique sets of summands by blackmanao

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