UPDATE:(Dec 1. 2008) further down the thread I admit and show that I was wrong in this node! No need to discuss it further
I don't think so, IMHO you are getting at first hand a list which is later reevaluated in scalar context!
... I'll run some tests to find the "truth" ; )
UPDATE:
I think your example is equivalent to
my @a= ( $str =~ /.{1,$ml}/g ) ;
$a=scalar @a;
print $a;
nevertheless is =~ evaluated in list-context!
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