Dear Monks, I have 2 files and I am taking the key values from one file and parsing in the other file for values. Now I am getting a problem of multiple values for the same key like this:- 
File 1 Looks like this:-
DAVID 31
DAVID 29
DAVID 41

File 2 looks like this:-
>DAVID
40 40 40 40 40 40 40 40 40 33 40 40 40 40 40 40 40 40 40 40 40 40 40 4
+0 40 40 40 40 40 40 40 40 40 40 40 40
>DAVID
40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 66 40 40 6 40 40 40 40 40
+ 40 40 40 40 40 40 29 40 40 40 6 40
>DAVID
40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 4
+0 40 40 99 40 40 40 40 40 40 4 40 40

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How can I deal with this since Perl Hash array supports only one value for a single key.
Actually I am doing it like this ,e.g,. If David value in File 1 is 31 then I search it in File 2 for 31 position and if 31 position in File 2 is >=20. Then my result looks like this:- 
RESULT FILE:-
DAVID 31 40
DAVID 29 40  # This line is not printed bcoz hash can take only single
+ key
DAVID 41 40  # This line is not printed bcoz hash can take only single
+ key

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Can you please suggest me how should I change my code to accommodate this short coming ?
Here is my sample code:- 
#!/usr/bin/perl -w
use strict;

  my %href;

      my $fn = <STDIN>;

      open(FH, "$fn") || die "Cannot open file";



      while (<FH>) {

              chomp($_);

              $href{$1} = $2 if $_ =~ /(\S+)\s+(\S+)/;

      }



      while (my ($key, $value) = each(%href)) {

              #print $key. ", ". $value."\n";

      }

open(FD,"<FileToBeParsedForValues.txt") || die("Can't open: $!");

$/ = '>';

while ( <FD> ) {

    chomp;

    next unless ( s{ \A (\S+) \s+ (?= \d ) }{}xms and exists( $href{$1
+} ));


    my $name = $1;

    my @numbers = split /\D+/;

    my $one_number = $numbers[$href{$name} - 1];

    if ( $one_number >= 20 ) {

        print "$name\t\t$href{$name}\t$one_number\n";

    }

}
close FD;

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In reply to Multiple Hash key values problem !! by ashnator

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