No! Doubles have 64-bits.

Of which:

• 1 bit is used for the sign;
• 11 bits are used for the exponent;
• 52 bits are used for the mantissa;
• 1 extra bit is implied in the mantissa by the specification;

With the result being that a 64-bit IEEE-754 double precision floating point value can act as a 53-bit signed integer for some purposes.

If you're going to try to be a pedant, rather than contribute something useful--at least be right.

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