Well it's a question of weird optimization, a constant scalar is passed in a certain snippet of code, so no need to switch the reference at runtime.
This works with explicit refs like [1,2] and {1,2} but not with constants, they needlessly get at runtime a new reference, each time the loop gets there...
just compare:
check(qw/ Scalarref \1 /);
OUTPUT
--- Scalarref
for (1..3) {
pr \1;
print "\n\t"; #UPDATE
for (1..3) {
pr \1;
}
print "\n";
}
REF(0x8190768)
REF(0x8190744) REF(0x8190750) REF(0x8190744)
REF(0x8190750)
REF(0x8195394) REF(0x8190744) REF(0x8195394)
REF(0x8190744)
REF(0x8190768) REF(0x8195394) REF(0x8190768)
each time a new ref instead of one ref
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