I'd probably use just bitwise math, but as you've asked for pack, here's one way:

$s = chr( 0xa8 ) . chr( 0x38 );; print unpack 'b*', $s;; 0001010100011100 print unpack 'A5A4A7', unpack 'b*', $s;; 00010 1010 0011100 print map{ unpack 'C', pack 'b*', $_ } unpack 'A5A4A7', unpack 'b*', $ +s;; 8 5 28 ( $day, $month, $year ) = map{ unpack 'C', pack 'b*', $_ } unpack 'A5A4A7', unpack 'b*', $ printf "%4d-%02d-%02d\n", 1980+$year, $month, $day;; 2008-05-08

Updated: Or using bitwise math:

$s = chr( 0xa8 ) . chr( 0x38 );; $n = unpack 's', $s;; ( $day, $month, $year ) = ( $n & 0x1f, ( $n & 0x1e0 ) >> 5, ( $n & 0xfe00 ) >> 9 );; printf "%4d-%02d-%02d\n", 1980+$year, $month, $day;; 2008-05-08

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In reply to Re: Practical Example of Converting Packed Value by BrowserUk
in thread Practical Example of Converting Packed Value by Jim

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