Notice how the LHS is a list even though there's no parens? You're confusing cause and effect. "($a)" is a list because "=" is a list assignment operator. "=" being a list assignment operator isn't caused by "($a)" being a list.

I have no doubt that the implementation on the opcode-level is differently done, BUT I'm arguing you can tell on the perl-level!

Do you know any perlcode, where () and (1,2) reacts as a list and (1) does not???

My thesis is that the implemantation is transparent in this aspect and one can easily say ($a) is a one element list to a "normal" perl programmer! Can you find any contradictory perl code? I can't!

Like in physics the easiest model is always preferable as long as you can't get to the extreme borders.

For instance as long as Bohr's Model predicts all experiments in your laboratory it's a sufficient model, no matter how complicated the underlying Quantum Mechanics are.

In other words: Normal Perl programmers don't need to see the matrix, Neo! 8 ) Or do you know an example where the matrix effects normal live??? I'm really eager to know ...

Cheers Rolf

In reply to Re^12: chopping a string into slices - is there a more elegant way to do it? by LanX
in thread chopping a string into slices - is there a more elegant way to do it? by rovf

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