Hello,
I have a problem in substitute 2 directory names, for e.g: 
$dir1="D:\\Windows\\programs1";
$dir2="D:\\Windows\\programs2";

$file1 = ="D:\\Windows\\programs1\\a.txt";

($file2 = $file1) =~ s/$dir1/$dir2/esg;

print "file1 -> $file1\n";
print "file2 -> $file2\n";

[download]
I expect to get - 
file1 -> D:\Windows\programs1\a.txt
file2 -> D:\Windows\programs2\a.txt

[download]
but i got - 
file1 -> D:\Windows\programs1\a.txt
file2 -> D:\Windows\programs1\a.txt

[download]
Any idea ?

Thanks in advance

azaria

In reply to problem in substitution by azaria

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