snowhare,
Can this be reduced even further? 
for values of x > 20
if x % 12 == 0 then x % 6 == 0

[download]
Is there a reason to have them both?

Update: In other words, order the list in descending order removing any exact multiples of previous items. When you reach 16, one of two things will happen. Either there will be a remainder and it will exit the loop or there won't be a remainder and it will continue. There is no need to test 8 after 16.

Cheers - L~R

In reply to Re^3: Why is this code so much slower than the same algorithm in C? by Limbic~Region
in thread Why is this code so much slower than the same algorithm in C? by wanna_code_perl

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