I also know nothing about Java. But, it looks like the Java "exec" is not treating the "\n" as a newline character. Or maybe the double quotes in Java are performing some type of interpolation. Does Java have any non-interpolation quotes, like single quotes (q) in Perl?

As a (lame) workaround, since you are performing a substitution on "\n" in your perl code, maybe you could use a different delimiter, like ":" 

Process p = Runtime.getRuntime().exec("c:/perl.exe"  C:/CreateER.pl "P
+lease : ignore : my friend");

[download]

then: 

s/:/\n/g;

[download]

Update: As an aside, your code spews a warning if you add use warnings; (verbose explanation provided by use diagnostics;): 

Scalar value @ARGV[1] better written as $ARGV[1] at ...
    (W syntax) You've used an array slice (indicated by @) to select a
    single element of an array.  Generally it's better to ask for a sc
+alar
    value (indicated by $).  The difference is that $foo[&bar] always
    behaves like a scalar, both when assigning to it and when evaluati
+ng its
    argument, while @foo[&bar] behaves like a list when you assign to 
+it,
    and provides a list context to its subscript, which can do weird t
+hings
    if you're expecting only one subscript.

    On the other hand, if you were actually hoping to treat the array
    element as a list, you need to look into how references work, beca
+use
    Perl will not magically convert between scalars and lists for you.
+  See
    perlref.

[download]

In reply to Re: Problem with the Perl/Java intergarion when new line break is used in the argument by toolic
in thread Problem with the Perl/Java intergarion when new line break is used in the argument by henrycui

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