This solution doesn't use modules at all.

use strict;
use warnings;

my $startDate = q{2007-11-23};
my $endDate   = q{2008-04-12};

my $leap = isLeap( ( split m{-}, $startDate )[ 0 ] );

my @dates = ( $startDate );
while( $startDate ne $endDate )
{
    $startDate = incByOneDay( $startDate );
    push @dates, $startDate;
}

print do{
   local $" = qq{\n};
   qq{@dates\n};
   };

sub incByOneDay
{
    my $raDaysInMonth = [
       [ 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ],
       [ 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ],
       ];

    my( $y, $m, $d ) = split m{-}, $_[ 0 ];
    $d ++;
    $d = 1, $m ++
       if $d > $raDaysInMonth->[ $leap ]->[ $m ];
    $m = 1, $y ++, $leap = isLeap( $y )
       if $m > 12;

    return sprintf q{%04d-%02d-%02d}, $y, $m, $d;
}

sub isLeap
{
    my $year = shift;
    return 0 if $year % 4;
    return 1 if $year % 100;
    return 1 unless $year % 400;
    return 0;
}

[download]

I would probably use modules if starting from scratch but I had this code lying around anyway so I thought I'd adapt it.

Cheers,

JohnGG

In reply to Re: Increment through date range by day with only standard modules. by johngg
in thread Increment through date range by day with only standard modules. by dbmathis

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