Hello Monks,

The following is a working perl script (progA.pl): 
#!/usr/bin/perl -P
use strict;
#define C 10

my $var = C;
print $var . "\n";

[download]
However, if I include that in another perl file as a library, it no longer works: 
#!/usr/bin/perl -P
require "progA.pl";

[download]
The problem is that the preprocessor (notice the -P switch) isn't processing included library files. Is there any way to make the preprocessor process included files?

Jim

Update: This is a contrived example. I simplified it for this forum to isolate the problem, which is the fact that the preprocessor ignores included library files. In reality, I have several perl library files which I created, and I want subroutines in those files to be able to call the same subroutine messageLog() and have it behave differently based on which file it was called from (so I can turn off/on message logging from a specific file). I don't know if I can do that with Perl syntax, but I know I can do it with macros: just define the macro for messageLog() at the beginning of each file.

In reply to Preprocessor, library files by James Board

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