That node seems to agree with me: Arrows are optional between two subscripts.

In $x->[0]->[1], $x is not a subscript but both [0] and [1] are. We may remove the second arrow without changing the expression, giving $x->[0][1]. The arrow between $x and [0] isn't between two subscripts, however, so it is required to maintain equivalence with the original expression.

--
Rocco Caputo - http://poe.perl.org/

In reply to Re^3: How can POE use a hash reference like a hash? by rcaputo
in thread How can POE use a hash reference like a hash? by sunshine_august

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