Not true. 

>perl -le"print length qq{\n}"
1

>perl -le"print unpack 'H*', qq{\n}"
0a

[download]

It's not true in C either. 

#include <string.h>
#include <stdio.h>

int main() {
   printf("%d\n", strlen("\n"));

   {
      const char* p = "\n";
      while (*p) {
         printf("%02x", *(p++));
      }
      printf("\n");
   }

   return 0;
}

[download]
1
0a

[download]

In Perl, LF gets converted to CRLF on input/output when the crlf PerlIO layer is used. While the string is in memory, you want to work with just LF, and \n is just LF.

In reply to Re^6: Detect line endings with CGI.pm upload by ikegami
in thread Detect line endings with CGI.pm upload by apu

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