Example that I saw in a page is as follows

sub f($$); //Function declaration.
@a = (5, 9);
Now we will see what will happen for different calls.

&f; The & bypasses subroutine prototypes, so the compiler won't complain about the subroutine call. The call also has no argument list, so it is called with its caller's @_.

&f(); f is called with an empty argument list. The & causes the subroutine prototypes to be bypassed.

f(); It won't compile because the prototype mismatch.

f; It won't compile again.

f(@a); It won't compile because the argument expected is scalars but passed is an array.

f(@a, @a); This will compile. The compiler interprets the @a in scalar context, so it will pass the no:of:elements in the array to the function.

&f(@a); This also compiles. The & disables prototype checking, so @a becomes the @_ of the subroutine. This is equivalent to f(5,9).

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