I have three types of URL's:
http://www.url.com
http://www.url.com/
http://www.url.com/cgi.pl?x=y

I want to strip off the stuff that isn't the domain name. So the above URL's would become:
http://www.url.com or http://www.url.com/
* Note I want the trailing "/" if it's after the domain name

This is my stab at it: 
#!/usr/bin/perl -w
use strict;

my $displayed_link = 'http://www.url.com/cgi.pl?x=y';

( $displayed_link ) = $displayed_link =~ m/^(http:\/\/.*?\/)/;

print $displayed_link . "\n";

[download]
Notice that I get the URL out, but if it's just a plaint http://www.url.com without a trailing slash it gets an error.
#!/usr/bin/perl -w
use strict;

my $displayed_link = 'http://www.url.com';

( $displayed_link ) = $displayed_link =~ m/^(http:\/\/.*?\/)/;

print $displayed_link . "\n";

[download]
I've tried a bunch of ways to have it come out with "http:www.url.com" or "http://www.url.com/" regardless of the input but can't figure it out.

What's the proper way to do this?

In reply to Regex Question by Anonymous Monk

Title:
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