My $0.02: 
perl -e 'for my $d(0..127){
            for (0..3){
               next unless ($d & 3<<($_+$_))==0;
               $count++; 
            }
          };
           print qq|\nCount=$count\n|'

[download]
prints:
Count=160

I also considered using 'grep' instead of the inner loop - but this is somewhat clearer.

     ..to maintain is to slowly feel your soul, sanity and sentience ebb away as you become one with the Evil.

In reply to Re: binary string by NetWallah
in thread binary string by alih110

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