Posting code, particularly line 325, would be helpful. What is happening is your syntax is telling the interpreter to think the string is supposed to contain a symbolic reference (see perlref). One possible way you may have done this is the code ${$string}. If the content of the string is "0" at that point, the symbolic reference is interpreted as a reference to the variable $0, which I strongly suspect you did not intend. I would likely be a very good idea to leave use strict; in effect and fix what is likely a typo in line 325.

In reply to Re: converting from string to SCALAR when using strict "refs" by kennethk
in thread converting from string to SCALAR when using strict "refs" by usrlocal

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