1. print can take a list as an argument, thus the return value (1 ie. true) of the print"no" gets printed (comma is a list separator).
  2. exit gets evaluated and your script exits.
  3. The last part of your statement is evaluated first, that means that if( $var ) exit is executed first and it exits.

Update: corrected #2, thanks ikegami

--
seek $her, $from, $everywhere if exists $true{love};

In reply to Re: strange behaviour in perl ..please explain by puudeli
in thread strange behaviour in perl ..please explain by perlplayer

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