Evidently, the
// are matching
$_, which even though it is undefined is treated as the null string, which happens to match. The
\ is also providing a scalar context.
Note that the eval is somewhat superfluous, try
perl -e '$_="."; $r=\-d; print $r, "\n", $r + 0, "\n", $$r, "\n";'
Also, your perl or OS appears to have address space randomization (security feature); some machines return the same numbers every time.
It kinda looks to me like 0+\ might be able to distinguish values depending on how they were arrived at.
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