Hello Monks, I'm trying to remove a block of lines before & after my regex match, and orignally tried it using grep like: grep -v -B 5 -A 3 somestring ./somefile.txt But unable to get the -B (num lines before) and -A (num lines after) to work with with-v (invert) at the same time. So, I'm thinking perl will do the job. Anybody have any ideas how I can do this with perl using the command line arg as the string to match on then removing 5 lines before and 3 lines after the matched string; also removing the line of the string searched. Thanks, Jim

In reply to Regex question by jamsda

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