It can be done with one regexp.
/^(?=.*a)(?=.*b)(?=.*c).*d/ or die;

If you want to know the order in which they came,

my %order; @order{qw( a b c d )} = map length, /^(?=(.*?)a)(?=(.*?)b)(?=(.*?)c)(.*?)d/ or die; my @ordered = sort { $order{$a} <=> $order{$b} } keys %order;

This is probably slow for long strings.

Update: Actually, no need for a hash.

my @order = map length, /^(?=(.*?)a)(?=(.*?)b)(?=(.*?)c)(.*?)d/ or die; my @ordered = ( qw( a b c d ) )[ sort { $order[$a] <=> $order[$b] } 0..$#order ];

Update: Back to the practical, using multiple regexp and saving @- should be much faster. Especially if scanning for constants.

my @unordered = qw( a b c d ); my @order; for my $s (@unordered) { push @order, /\Q$s/ ? $-[0] : die; } my @ordered = @unordered[ sort { $order[$a] <=> $order[$b] } 0..$#order ];

In reply to Re: How to replace greedy alternation? by ikegami
in thread How to replace greedy alternation? by adamcrussell

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