Just because perl issues a warning, it doesn't mean perl doesn't do the right thing. It's true, converting "0x000fffff7f00fffc" with hex is non-portable as it won't do the same thing on a 32-bit perl (to which I say, so what? Adding number isn't portable either, as you may get different results as well, but addition doesn't come with a warning). 
$ perl -wE 'say hex "0x000fffff7f00fffc"'
Hexadecimal number > 0xffffffff non-portable at -e line 1.
4503597463175164

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Just use your 64-bit perl, and turn off the warning. 
perl -E 'say hex "0x000fffff7f00fffc"'
4503597463175164

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In reply to Re: Is there a 64-bit hex()? by JavaFan
in thread Is there a 64-bit hex()? by kornerr

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