Regarding Update 2:

The problem is that $db{$var1} is an array reference, not a hash reference. Perhaps you mean $db{$var1}[$indice]{counter} = '';?

As a second note, so long as your hash keys contain only alphanumerics and underscores, Perl will automatically stringify the result - there's no need for quotes.

In reply to Re: Check if value exists into an array in a hash by kennethk
in thread Check if value exists into an array in a hash by Sombrerero_loco

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