Thanks for the link.

But i studied that already and i struck with this example.

I am confused how the $foo variable is locked in the functions.

Please explain the locking in this code , if you get anything. i am asking very basic things i guess :(

In reply to Re^2: Help on Understanding Locks in Multithreading by koti688
in thread Help on Understanding Locks in Multithreading by koti688

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