Shouldn't perl -T -e"do'./t\t.pl'" and perl -T -e"do'.\t\t.pl'" do the same thing

Yes. "/" and "\" are equivalent in Windows paths.

I can replicate the problem with ActivePerl 5.6.0, 5.6.1, 5.8.0, 5.8.8, 5.10.0.

Seems the logic for whether @INC should be used or not is broken. Under -T, @INC doesn't contain ".", and do'.\t\t.pl' is using @INC instead of the cd.

(and print 'hi').

Seems so. 5.8.8 on linux: 

$ perl -le'@INC=(); do "t/t.pl"'

$ perl -le'@INC=(); do "./t/t.pl"'
hi

$ perl -T -le'@INC=(); do "t/t.pl"'

$ perl -T -le'@INC=(); do "./t/t.pl"'
hi

[download]

Update: Added comparison to linux and explanation of problem.

In reply to Re: do'.\dir\file' under -T on Windows by ikegami
in thread do'.\dir\file' under -T on Windows by lamprecht

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