Just to be different (and because I don't like two element ranges): 
#!/usr/bin/perl

my(@yearArray) = (1992, 1994, 1995, 1997, 1998, 1999, 2000, 2002, 2004
+, 2005, 2006, 2007, 2008);

my($anchor) = shift(@yearArray);
my(@out) = $anchor;

while (@yearArray > 1) {
  my $tmp = shift(@yearArray);
  push(@out, ($yearArray[0] == $anchor + 2 ? '-' : $tmp));
  $anchor = $tmp;
}
push(@out, @yearArray);

my $out = join(', ', @out);
$out =~ s/(, -)+, /-/g;

print $out, "\n";

[download]

This assumes that each element of @yearArray is numeric and that it is sorted in ascending order.

In reply to Re: How do I easily turn a year array into a string by eye
in thread How do I easily turn a year array into a string by Drigan

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