Why doesn't this work?

$ perl -le'do { print $i++; last if $i>5 } while 1; print "end"'
0
1
2
3
4
5
Can't "last" outside a loop block at -e line 1.

while (no pun intended) this works:

$ perl -le'while (1) { print $i++; last if $i>5 } print "end"'
0
1
2
3
4
5
end

Isn't do {} while as much a loop as while () {}?

In reply to last in do vs last in while/for by dgaramond2

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