sub testing(){
    foreach(@_){
        print $_;
    }
}

my $subref=\&testing(1,2,3,4,6);
print Dumper $subref;
my $subref=\&testing;

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In the above code I tried to get the reference to a subroutine, When I try the first one with parameter it called the function and the return value's reference is saved in the $subref variable

In the second one I tried without parameter the subroutine's reference saved in the $subref variable

How these two interpreted differently in Perl?

In reply to Subroutine reference by vinoth.ree

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