From perldiag: 

=item %s() called too early to check prototype

(W prototype) You've called a function that has a prototype before the parser saw a
definition or declaration for it, and Perl could not check that the call
conforms to the prototype.  You need to either add an early prototype
declaration for the subroutine in question, or move the subroutine
definition ahead of the call to get proper prototype checking.  Alternatively,
if you are certain that you're calling the function correctly, you may put
an ampersand before the name to avoid the warning.  See L<perlsub>.

Cheers,
KM

In reply to Re: What does called to early mean? by KM
in thread What does called to early mean? by HeffaK

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