No, it still has the '0' false negative:

$ perl -e '$x = 0; print "failed\n" unless $x and length($x)' failed $

vs.

$ perl -e '$x=0; $ print "failed\n" unless defined $x and length($x)' $


In reply to Re^2: testing defined($x) && length($x) by kennethk
in thread testing defined($x) && length($x) by perl5ever

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