Why doesn't this code generate a warning or error? Expected the attempt to dereference the undef value, $array_ref->[0], would result in an error or at least warning. 
use strict;
use warnings;

my $array_ref = [undef];

if ($array_ref-> [0]->{whatever}){
    print "true";
}
else {
    print "false";
}

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In reply to Why nothing from 'strict' or 'warnings' with deref'd undef value? by jeremym

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