"isn't really a closure.."

Exactly, even though it technically is a real closure. The unnamed sub will remember the value of $type as long as the sub exists (in that sense it is a closure). But since $type isn't used anywhere in the unnamed sub, it is of no consequence.

In reply to Re^3: Syntax question about closures and Perl 'sort' by jethro
in thread Syntax question about closures and Perl 'sort' by dwm042

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